Penyelesaian:
f(x+1)=2f(x)
f(1+1)=2f(1)
f(2)=2×6
f(2)=12
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f(2+1)=2f(2)
f(3)=2(12)
f(3)=24
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f(3+1)=2f(3)
f(4)=2(24)
f(4)=48
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Maka ini adalah barisan geometri.
f(1),f(2),f(3),f(4),…
6,12,24,48,…
r=12÷6=2
a=6
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U7=a.rⁿ-¹
U7=6.2⁷-¹
U7=6.2⁶
U7=6.64
U7=384
[tex] \boxed{ \colorbox{black}{ \sf{ \color{lightgreen}{ answered\:by\:Duone}}}} [/tex]
Materi : Fungsi dan Relasi
Suku ke - 1, 2, dan 3
___________
f( 1 + 1 ) = 2f(1)
f(2) = 2(6)
f(2) = 12
___________
f( 2 + 1 ) = 2f(2)
f(3) = 2(12)
f(3) = 24
___________
f( 3 + 1 ) = 2f(3)
f(4) = 2(24)
f(4) = 48
Pola barisan geometri
f(1), f(2), f(3), f(4), ...
6, 12, 24, 48, ...
Suku pertama = 6 dan rasio = 2
Rumus pola : Un = 6 × 2ⁿ-¹ atau 3 × 2ⁿ
Suku ke - 7 { f(7) }
f(x) = 3 × 2^×
f(7) = 3 × 2⁷
f(7) = 3 × 128
f(7) = 300 + 60 + 24
f(7) = 384
Semoga bisa membantu
[tex] \boxed{ \colorbox{lightblue}{ \sf{ \color{blue}{ By\:BlueBraxGeometry}}}} [/tex]
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